Hindawi Publishing Corporation ξ e Scientiο¬c World Journal Volume 2014, Article ID 901726, 10 pages http://dx.doi.org/10.1155/2014/901726
Research Article On πΉ-Algebras ππ (1 < π < β) of Holomorphic Functions Romeo MeΕ‘troviT Maritime Faculty, University of Montenegro, Dobrota 36, 85330 Kotor, Montenegro Correspondence should be addressed to Romeo MeΛstroviΒ΄c;
[email protected] Received 31 August 2013; Accepted 4 November 2013; Published 28 January 2014 Academic Editors: A. Ibeas and G.-Q. Xu Copyright Β© 2014 Romeo MeΛstroviΒ΄c. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We consider the classes ππ (1 < π < β) of holomorphic functions on the open unit disk D in the complex plane. These classes are in fact generalizations of the class π introduced by Kim (1986). The space ππ equipped with the topology given by the metric 1/π
2π
ππ defined by ππ (π, π) = βπ β πβπ = (β«0 logπ (1 + π(π β π)(π))(ππ/2π)) , with π, π β ππ and ππ(π) = sup0β©½π π) ,
β π»π β β π π , π>0
β ππ β π β π+ β π,
2π
σ΅¨ σ΅¨ π ππ sup β« (log+ σ΅¨σ΅¨σ΅¨σ΅¨π (ππππ )σ΅¨σ΅¨σ΅¨σ΅¨) < +β. 2π 00 defined for π β πΉπ as β
σ΅¨ βππ1/(π+1) σ΅¨ σ΅¨σ΅¨σ΅©σ΅© σ΅©σ΅©σ΅¨σ΅¨ < β, σ΅¨σ΅¨σ΅©σ΅©πσ΅©σ΅©σ΅¨σ΅¨π,π = β σ΅¨σ΅¨σ΅¨σ΅¨πΜ (π)σ΅¨σ΅¨σ΅¨σ΅¨ π
(11)
π=0
Μ is the πth Taylor coefficient of π, for each π > 0, where π(π) becomes a countably normed FrΒ΄echet algebra. By a result of Eoff [7, Theorem 4.2], πΉπ is the FrΒ΄echet envelope of ππ , and hence πΉπ and ππ have the same topological duals. Here, as always in the sequel, we will need some of Stollβs results concerning the spaces πΉπ only with 1 < π < β, and hence we will assume that π = π > 1 is any fixed number. The study of the class π has been extensively investigated by Kim in [1, 2], Gavrilov and Zaharyan [18], and Nawrocky [19]. Kim [2, Theorems 3.1 and 6.1] showed that the space π with the topology given by the metric π defined by 2π
0
ππ , 2π
2π
π ππ
β« (log+ ππ (π)) (10)
|π§|β€π
π (π, π) = β« log (1 + π (π β π) (π))
Μ is the πth Taylor coefficient of for each π > 0, where π(π) + π. Notice that πΉ coincides with the space πΉ1 defined above. It was shown in [17, 21] that πΉ+ is actually the containing FrΒ΄echet space for π+ . Moreover, Nawrocky [19, Theorem 1] characterized the set of all continuous linear functionals on π which by a result of Yanagihara [17] coincides with those on the Smirnov class π+ . Motivated by the mentioned investigations of the classes π and π+ , and the fact that the classes ππ (1 < π < β) are generalizations of the Smirnov class π+ , in Section 2, we consider the classes ππ (1 < π < β) as generalizations of the class π. Accordingly, the class ππ (1 < π < β) consists of all holomorphic functions π on D for which
0
σ΅¨ σ΅¨ πβ (π, π) = max σ΅¨σ΅¨σ΅¨π (π§)σ΅¨σ΅¨σ΅¨ .
(13)
π=0
becomes an πΉ-algebra. Recall that the function π1 = π defined on the Smirnov class π+ by (8) with π = 1 induces the metric topology on π+ . Yanagihara [17] showed that, under this topology, π+ is an πΉ-space. Furthermore, in connection with the spaces ππ (1 < π < β), Stoll [6] (also see [7] and [12, Section 3]) also studied the spaces πΉπ (0 < π < β) (with the notation πΉ1/π in [6]), consisting of those functions π holomorphic on D for which lim (1 β π)1/π log+ πβ (π, π) = 0,
β σ΅¨ βπβπ σ΅¨ σ΅¨σ΅¨σ΅©σ΅© σ΅©σ΅©σ΅¨σ΅¨ < β, σ΅¨σ΅¨σ΅©σ΅©πσ΅©σ΅©σ΅¨σ΅¨π := β σ΅¨σ΅¨σ΅¨σ΅¨πΜ (π)σ΅¨σ΅¨σ΅¨σ΅¨ π
1/π
π, π β ππ (8)
πβ1
becomes an πΉ-algebra. Furthermore, Kim [2, Theorems 5.2 and 5.3] gave an incomplete characterization of multipliers of π into π»β . Consequently, the topological dual of π is not exactly determined in [2], but, as an application, it was proved in [2, Theorem 5.4] (also cf. [19, Corollary 4]) that π is not locally convex space. Furthermore, the space π is not locally bounded ([2, Theorem 4.5] and [19, Corollary 5]). Although the class π is essentially smaller than the class π+ , Nawrocky [19] showed that the class π and the Smirnov class π+ have the same corresponding locally convex structure which was already established by Yanagihara for the Smirnov class in [17, 20]. More precisely, it was proved in [19, Theorem 1] that the FrΒ΄echet envelope of the class π can be identified with the space πΉ+ of holomorphic functions on the open unit disk D such that
π, π β π (12)
2π
< β.
(14)
Obviously, β ππ β π.
(15)
π>1
Following [2], by analogy with the space π, the space ππ is equipped with the topology induced by the metric ππ defined as σ΅© σ΅© ππ (π, π) = σ΅©σ΅©σ΅©π β πσ΅©σ΅©σ΅©π 2π
(16)
1/π
ππ = (β« log (1 + π (π β π) (π)) ) 2π 0 π
,
with π, π β ππ . In Section 2, we give the integral limit criterion for a function π holomorphic on the disk D to belong to the class ππ (Lemma 3). Furthermore, we prove that the space ππ is closed under integration (Theorem 4). In Section 3 we study and compare the uniform convergence on compact subsets of D and the convergences induced by the metrics ππ and ππ in the space ππ , respectively. It is proved (Theorem 11) that ππ = ππ for each π > 1.
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It is proved in Section 4 that the space of all polynomials on C is a dense subset of ππ (Theorem 13). Hence, ππ is a separable metric space. We show that the space ππ with the topology given by the metric ππ becomes an πΉ-space (Theorem 15). As an application, we prove that the metric spaces (ππ , ππ ) and (ππ , ππ ) have the same topological structure (Theorem 16). Consequently, we obtain a characterization of continuous linear functionals on ππ (Theorem 17). Notice that Theorem 17 with π = 1 characterizes the set of all continuous linear functionals on the space π, which is in fact the Nawrocky result [19, Theorem 1] mentioned above. In Section 5 we obtain a characterization of bounded subsets of the spaces ππ (= ππ ) (Theorem 19). It is also given another necessary condition for a subset of ππ (ππ ) to be bounded (Theorem 22). Finally, we give the examples of bounded subsets of ππ that are not relatively compact (Theorem 24).
2. The Classes ππ (1 < π < β) Recall that, for a fixed 1 < π < β, the class ππ consists of all holomorphic functions π on D for which
Theorem 2. The function ππ defined on ππ as σ΅© σ΅© ππ (π, π) = σ΅©σ΅©σ΅©π β πσ΅©σ΅©σ΅©π 2π
= (β« logπ (1 + π (π β π) (π)) 0
1/π
ππ ) 2π
,
(23)
π, π β ππ is a translation invariant metric on ππ . Further, the space ππ is a complete metric space with respect to the metric ππ . Proof. If we suppose that ππ (π, π) = 0, for some π, π β ππ , then by (23) it follows that π(π β π)(π) = 0 for almost every π β [0, 2π]. Hence, πβ (πππ ) = πβ (πππ ) for almost every πππ β T, and, by Riesz uniqueness theorem, we infer that π(π§) = π(π§) for all π§ β D. As, by (19), the triangle inequality is satisfied, it follows that ππ is a metric on ππ . Finally, by the obvious inequality π, π, β β ππ ,
ππ (π + β, π + β) = ππ (π, π) ,
(24)
(17)
we see that ππ is a translation invariant metric. This concludes the proof.
Combining the inequalities log(|π| + 1) β€ log+ |π| + log 2 and (|π| + |π|)π β€ 2πβ1 (|π|π + |π|π ), we obtain logπ (|π| + 1) β€ 2πβ1 ((log+ |π|)π + (log 2)π ) (π, π, π β C). The last inequality implies the fact that the condition (17) is equivalent to
For simplicity, here as always in the sequel, we shall write ππ instead of the metric space (ππ , ππ ). For a function π holomorphic in D and for any fixed 0 β€ π < 1, denote by ππ the function defined on D as ππ (π§) = π(ππ§), π§ β D. Furthermore, for a given holomorphic function π on D, let
2π
+
π ππ
β« (log ππ (π)) 0
2π
2π
< β.
1/π
π ππ σ΅©σ΅© σ΅©σ΅© ) σ΅©σ΅©πσ΅©σ΅©π := (β« (log (1 + ππ (π))) 2π 0
< β.
(18)
Lemma 1. The function β β
βπ defined on ππ by (18) satisfies the following conditions: σ΅© σ΅© σ΅© σ΅© σ΅© σ΅©σ΅© π σ΅©σ΅©π + πσ΅©σ΅©σ΅©π β€ σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©π + σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©π βπ, π β π , (19) σ΅©σ΅©σ΅©ππσ΅©σ΅©σ΅© β€ σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅© βπ, π β ππ . (20) σ΅© σ΅©π σ΅© σ΅©π σ΅© σ΅©π
σ΅¨ σ΅¨ σ΅¨ σ΅¨ πππ (π) = sup σ΅¨σ΅¨σ΅¨ππ (π)σ΅¨σ΅¨σ΅¨ = sup σ΅¨σ΅¨σ΅¨σ΅¨π (ππππ )σ΅¨σ΅¨σ΅¨σ΅¨ , 0β€πβ€π 0β€πβ€π
(25) Lemma 3. A function π holomorphic on the unit disk D belongs to the class ππ if and only if it satisfies 2π
π ππ
lim β« (log+ πππ (π))
πβ1 0
Hence, ππ is an algebra with respect to the pointwise addition and multiplication of functions.
2π
2π
π ππ
+
= β« (log ππ (π)) 0
Proof. Combining the inequality
0 β€ π < 1.
2π
(26) < β.
Proof. The condition (26) implies that π β ππ . Conversely, assume that π β ππ . Then
log (1 + π (π + π) (π)) β€ log (1 + ππ (π)) + log (1 + ππ (π)) ,
πππ (π) σ³¨β ππ (π) as π σ³¨β 1
(21)
π, π β ππ with Minkowskiβs integral inequality (with the power π), we immediately obtain (19). Similarly, combining the inequality log (1 + π (ππ) (π)) β€ log (1 + ππ (π)) + log (1 + ππ (π)) ,
(27)
for almost every π β [0, 2π] .
(22)
π
π, π β π
with Minkowskiβs integral inequality (with the exponent π), we obtain (20).
Since, by the assumption, π β ππ ; that is, 2π π β«0 (log+ ππ(π)) (ππ/2π) < β, using (27) and applying the Lebesgue dominated convergence theorem, we obtain 2π
π ππ
lim β« (log+ πππ (π))
πβ1 0
2π
2π
π ππ
= β« (log+ ππ (π)) 0
2π
, (28)
which completes the proof.
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Theorem 4. The space ππ is closed under integration.
So by the triangle inequality, for each π β₯ π, we have
Proof. For a given function π β ππ , define π§
π
0
0
ππ (ππ , (ππ )π ) β€ ππ (ππ , ππ ) + ππ (ππ , (ππ )π )
πΉ (π§) = β« π (π§) ππ§ = β« π (π‘πππ ) πππ ππ‘.
+ ππ ((ππ )π , (ππ )π )
(29)
β€ 2ππ (ππ , ππ ) + ππ (ππ , (ππ )π )
It follows that |πΉ(ππππ )| β€ ππ(π), and thus ππΉ(π) β€ ππ(π) for almost every π β [0, 2π]. Therefore πΉ β ππ , as desired.
3. Convergences in the Space ππ Theorem 5. For each function π β ππ , ππ β π in ππ as π β 1β. π
0 there is a π β N such that π 3
βπ, π β₯ π.
(38)
Proof. The inclusion ππ β ππ is obvious, and (38) follows by the definition of the metrics ππ and ππ . Lemma 8. The convergence with respect to the metric ππ of the space ππ is stronger than the metric of uniform convergence on compact subsets of the disk D. Proof. The assertion immediately follows from the inequality on [5, page 898], which implies that, for any function π β ππ and 0 β€ π < 1, we have 1+π σ΅¨ σ΅¨ max σ΅¨σ΅¨σ΅¨π (π§)σ΅¨σ΅¨σ΅¨ β€ exp (( ) |π§|=π 1βπ
as π σ³¨β 1 β .
ππ (ππ , ππ )
0 such that π ππ
β« (log+ ππ (π)) πΈ
2π
< π βπ β πΏ,
(57)
for every measurable set πΈ β T with the Lebesgue measure |πΈ| < πΏ; (iii) for all π > 0 there exists πΏ > 0 such that σ΅¨ σ΅¨ π ππ 0 such that logπ (1 + π) + 2πβ1 logπ 2πΏ + 2πβ1 π < ππ .
(60)
Therefore, ππ (πΌπ, 0) < π, from which it follows that πΌπΏ β π. Hence, πΏ is a bounded subset of ππ . (i)β(ii). Assume that πΏ is a bounded subset of ππ . Then for any given π > 0 there is a πΌ0 = πΌ0 (π), 0 < πΌ0 < 1, such that 0
2 (π β 1) π 2ππ , )} , π π
π = 1, 2, . . . , π.
ππ < ππ 2π
2π
π ππ
β« (log+ |πΌ| ππ (π)) 0
< ππ
2π
(68)
for each π β πΏ, |πΌ| β€ πΌ0 . Since
(61)
1 , πΌ0
(69)
(log+ ππ (π)) β€ 2πβ1 ((log+ πΌ0 ππ (π)) + (log
1 π ) ). πΌ0 (70)
log+ ππ (π) β€ log+ πΌ0 ππ (π) + log
Then |πΈπ | = 1/π < πΏ, and thus by (iii) we have we obtain
2π σ΅¨ σ΅¨ π ππ β« (log+ σ΅¨σ΅¨σ΅¨σ΅¨πβ (πππ )σ΅¨σ΅¨σ΅¨σ΅¨) 2π 0
π
(62)
π
π
= β β« < ππ βπ β πΏ. π=1 πΈπ
For given π > 0, choose π > 0 satisfying
By (62) and Chebyshevβs inequality, we conclude that for every function π β ππ there exists a measurable set πΈπ β T depending on π such that σ΅¨ σ΅¨ π ππ (log+ σ΅¨σ΅¨σ΅¨σ΅¨πβ (πππ )σ΅¨σ΅¨σ΅¨σ΅¨) β€ πΏ
σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨T \ πΈπ σ΅¨σ΅¨σ΅¨ < πΏ, σ΅¨ σ΅¨
on πΈπ . (63)
π
0 such that
From (63), we obtain 1/π
(67)
for each π β πΏ and |πΌ| β€ πΌ0 . It follows that
Now it follows that there exists πΏ, 0 < πΏ < π, such that (iii) holds. Choose an π β N for which 1/π < πΏ. Set πΈπ = {πππ : π β [
2π
π
(ππ (πΌπ, 0)) = β« logπ (1 + |πΌ| ππ (π))
ππ 2π
logπ 2
ππ σ΅¨ σ΅¨ π ππ (log+ σ΅¨σ΅¨σ΅¨σ΅¨πβ (πππ )σ΅¨σ΅¨σ΅¨σ΅¨) +β« ) 2π 2π T\πΈπ
β€ logπ (1 + π) + 2πβ1 logπ 2πΏ + 2πβ1 π
Remark 20. Note that the condition (ii) from Theorem 19 π : π β πΏ} in fact means that the family {(log+ ππ(π)) is uniformly integrable on T. The same assertion is also valid for the condition (iii). On the other hand, from the proof of Theorem 19, we see that (ii) implies that the family π {(log+ ππ(π)) : π β πΏ} forms a bounded subset of the space 1 πΏ (T); that is, there holds 2π
< ππ . (66)
lim sup β« (log+ ππ (π)) πβπΏ
0
π ππ
2π
< +β.
(74)
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Similarly, it follows from (iii) that the π {(log+ |πβ (πππ )|) : π β πΏ} is bounded in πΏ1 (T).
family
for almost every πππ β πΈπ . From (78)β(80), we obtain σ΅¨ σ΅¨ π (log+ σ΅¨σ΅¨σ΅¨σ΅¨π (ππππ )σ΅¨σ΅¨σ΅¨σ΅¨) = β« + β«
π
Corollary 21. If πΏ is a subset of π for which the family
πΈπ
σ΅¨ σ΅¨ π {(log σ΅¨σ΅¨σ΅¨σ΅¨πβ (πππ )σ΅¨σ΅¨σ΅¨σ΅¨) : π β πΏ} +
Proof. The condition of Corollary 21 and (iii)β(ii) of Theorem 19 immediately yield that the family π {(log+ ππ(π)) : π β πΏ} is uniformly integrable on the circle T. This fact and the obvious inequality |π(ππππ )| β€ ππ(π), π β ππ , 0 β€ π < 1, for almost every π β [0, 2π], imply that π the family {(log+ |π(ππππ )|) : π β πΏ, 0 β€ π < 1} is uniformly integrable. The following result gives a necessary condition for a subset of ππ (= ππ ) to be bounded. Theorem 22. Let πΏ be a subset of ππ . If πΏ is bounded in ππ , then (1 β π)
) 1/π
Proof. By the inequqlity (5.4) from the proof of Theorem 5.2 in [4], for all π β ππ , we have σ΅¨ σ΅¨ π (log+ σ΅¨σ΅¨σ΅¨σ΅¨π (ππππ )σ΅¨σ΅¨σ΅¨σ΅¨)
(1 β ππ ) ππ ππ + < ππ , πΏπ 2
(83)
where ππ = πΏ(ππ ) and ππβ1 < ππ < 1,
ππ β 1
as π σ³¨β β.
(84)
Put π1 (π) = ππ
for ππ β€ π < ππ+1 ,
π = 1, 2, . . . .
(85)
β 0 β€ π < 1.
(86)
From (82), (83), and (85) we obtain π
(log+ πβ (π, π)) β€
π1 (π) 1βπ
Since π1 (π) σ³¨β 0
as π σ³¨β 1,
(87)
we conclude that there exists a continuous function π2 (π) satisfying π1 (π) β€ π2 (π) ,
π
(log+ πβ (π, π)) β€
π2 (π) β 0
as π β 1.
(88)
As, by the assumption, πΏ is a bounded subset of π , by Theorem 19 (iii), for all π > 0 there exists πΏ = πΏ(π) > 0, such that σ΅¨ σ΅¨ π ππ π < β« (log+ σ΅¨σ΅¨σ΅¨σ΅¨πβ (πππ )σ΅¨σ΅¨σ΅¨σ΅¨) 2π 2 0
βπ β πΏ
(79)
and for every measurable set πΈ β T with the Lebesgue measure |πΈ| < πΏ. Further, from the proof of (iii)β(i) of Theorem 19, we see that for each π β ππ there is a measurable set πΈπ β T depending on π for which σ΅¨ σ΅¨ π ππ (log+ σ΅¨σ΅¨σ΅¨σ΅¨πβ (πππ )σ΅¨σ΅¨σ΅¨σ΅¨) β€ πΏ
(80)
π2 (π) 1βπ
for each 0 β€ π < 1,
(89)
whence by setting
π
σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨T \ πΈπ σ΅¨σ΅¨σ΅¨ < πΏ, σ΅¨ σ΅¨
(82)
Therefore,
1 β π2 1 2π σ΅¨ σ΅¨ π (log+ σ΅¨σ΅¨σ΅¨σ΅¨πβ (πππ‘ )σ΅¨σ΅¨σ΅¨σ΅¨) ππ‘. β« 2π 0 1 β 2π cos (π β π‘) + π2 (78)
2π
(1 β π) ππ π + . πΏ 2
Choose a sequence {ππ } of positive numbers such that ππ β 0. For each π β N, let ππ > 0 be a number such that
πππ πππβ π β πΏ, (77)
where πβ (π, π) = max0β€π