84

LETTERS TO THE EDITOR

Second, they suggest that associations of n chromosomes, where n > 2, can be dealt with by partitioning them into their n (n -1)/2 constituent pairs, and assert that parameter estimates based on treating the resulting pairs as separate observations, are unbiased. I offer the following as a counter-example. Let there be three objects, 01, 02, and 03 representing individual chromosomes in a single cell. Suppose Oi is assigned independently of the other objects with probability Pi to one box and probability (1 Pi) to another. After assigning all three objects in this way, we define those that are in the first box as forming a single "association." This, therefore, represents a model of random association (in the sense that each object enters or fails to enter an association independently of the others), but in which each object has a different probability of association. The probabilities of the four kinds of associations are then, P12 = P1P2( -

P3),P23 =P2P3G -Pl),P31 =P3P1(l P2), andP123 =PIP2P3-

The expected relative numbers of the pairwise associations on their own are: P12 : P23 P31 = P1P2(l - p3) : P2P3(l - Pi) : P3P(l - P2), whereas in combination with the partitioned pairs from the triple association, they are: P12' : P23' : P31' = [p1P2(l - p3) + P1P2P3] P2P3(l - P1) + P1P2P3] P3P1(l - P2) + P1P2P3] = P1P2 :P2P3 :P3P1In general, the two sets of ratios are not equal and will provide different estimates of the pi. A. D. CAROTHERS MRC Clinical and Population Cytogenetics Unit Western General Hospital Edinburgh, Scotland REFERENCES JACOBS PA, MAYER M, MORTON NE: Acrocentric chromosome associations in man. Am J Hum Genet 28:567-576, 1976

RESPONSE TO CAROTHERS' LETTER

To the Editor: For clarity we answer the two points raised by Mr. Carothers in reverse order. The argument for "partitioning an association of n chromosomes into all n(n 1)/2 pairs" is given on p. 571 of our paper. We cannot imagine under what circumstances it would be interesting to discard multiples with n > 2, as in the proposed counter-example, even if allowance were made for the excluded class. Mr. Carothers shows that analysis according to our prescription gives unbiassed estimates as we asserted. The formula he questions is a special case of the familiar result due to Wright [1], f pi2 +pi (1 -pi)F fori=j p for i fj I2pi pj (I -F) where the pi are frequencies with which chromosomes enter into association, and F is the correlation between associated pairs, assumed constant.

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LETTERS TO THE EDITOR

The restriction 0 c Pij s 1 implies -pil(1-pi) ' F ' 1 for all Pi. In applications, this restriction has not been found to be a logical or practical difficulty. The most special case is pi = 21N, F = - I(N - 1), and each restriction may be relaxed separately. We showed thatp1 # 21N, and F --/(N - 1). It is indeed possible that some other theory would give a better fit to the data. The important consideration is that any hypothesis be tested. NEWTON E. MORTON PATRICIA A. JACOBS MARTHA MAYER University of Hawaii Honolulu, Hawaii 96822

REFERENCES 1.

WRIGHT S: Systems of mating. II. The effects of inbreeding on the genetic composition of a

population. Genetics 6:124-143, 1921

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Response to Carothers' letter.

84 LETTERS TO THE EDITOR Second, they suggest that associations of n chromosomes, where n > 2, can be dealt with by partitioning them into their n (...
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